Verified [year] NECO Further Mathematics Questions June/July Answers (100%) [Essay & Obj]

NECO Objective & essay Further Maths answers is ready. If you are SSCE candidate, see verified [year] NECO Further Mathematics Questions and Answers, and also how the examination is set. The National Examinations Council is an examination body in Nigeria that conducts the Senior Secondary Certificate Examination and the General Certificate in Education in June/July and November/December respectively.

We wish to inform all candidate for NECO [year] Further Mathematics exam, that the much awaited expo answers are now ready and uploaded here.

It is important to know that all answers uploaded by edureport team in this page has been verified, and certified to be according the NECO marking scheme.

NECO has scheduled the Further Mathematics examinations for Monday, 1st July 2024, starting with Paper III: Objective from 10:00 am to 12:00 noon, followed by Paper II: Essay from 12:00 noon to 2:30 pm.

Also read: NECO Technical drawing Questions and answers

[year] NECO Further Mathematics Questions June/July Answers

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NECO Further Maths Essay Answers

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NECO Further Mathematics Objective Answers

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[pyear] Further Mathematics answers

Question 1: 2×2−5x+2=02x^2 – 5x + 2 = 02x2−5x+2=0

Solution 1: To solve the quadratic equation 2×2−5x+2=02x^2 – 5x + 2 = 02x2−5x+2=0, use the quadratic formula: x=−b±b2−4ac2ax = \frac{-b \pm \sqrt{b^2 – 4ac}}{2a}x=2a−b±b2−4ac​​ where $a=2$, $b=-5$, and $c=2$.

Calculate the discriminant: Δ=(−5)2−4⋅2⋅2=25−16=9\Delta = (-5)^2 – 4 \cdot 2 \cdot 2 = 25 – 16 = 9Δ=(−5)2−4⋅2⋅2=25−16=9

Now, substitute the values into the formula: x=5±34x = \frac{5 \pm 3}{4}x=45±3​

Thus, the solutions are: x=2andx=12x = 2 \quad \text{and} \quad x = \frac{1}{2}x=2andx=21​

Question 2: 3×2+2x−1x+2\frac{3x^2 + 2x – 1}{x+2}x+23x2+2x−1​

Solution 2: To simplify 3×2+2x−1x+2\frac{3x^2 + 2x – 1}{x+2}x+23x2+2x−1​, perform polynomial long division or use synthetic division.

Performing polynomial long division: 3×2+2x−1x+2=3x−4+7x+2\frac{3x^2 + 2x – 1}{x+2} = 3x – 4 + \frac{7}{x+2}x+23x2+2x−1​=3x−4+x+27​

Question 3: ∫0πsin⁡x dx\int_0^{\pi} \sin x \, dx∫0π​sinxdx

Solution 3: Evaluate the definite integral: ∫0πsin⁡x dx=2\int_0^{\pi} \sin x \, dx = 2∫0π​sinxdx=2

Question 4: log⁡2(x−1)+log⁡2(x+1)=2\log_2(x-1) + \log_2(x+1) = 2log2​(x−1)+log2​(x+1)=2

Solution 4: Solve the logarithmic equation: x=5x = \sqrt{5}x=5​

Question 5: Find the equation of the line passing through $(2,3)$ and $(-1,5)$.

Solution 5: Calculate the equation of the line: y=−23x+133y = -\frac{2}{3}x + \frac{13}{3}y=−32​x+313​

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To excel in NECO Further Mathematics exams, practice solving a wide range of problems across topics like calculus, algebra, and statistics to build proficiency and confidence. Additionally, familiarize yourself with exam formats and timing to effectively manage and allocate time during the assessment.

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